5/(x^2-x+6)=(3x-7)/(x-2)

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Solution for 5/(x^2-x+6)=(3x-7)/(x-2) equation: 


D( x )

x-2 = 0

x^2-x+6 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x^2-x+6 = 0

x^2-x+6 = 0

x^2-x+6 = 0

DELTA = (-1)^2-(1*4*6)

DELTA = -23

DELTA < 0

x in (-oo:2) U (2:+oo)

5/(x^2-x+6) = (3*x-7)/(x-2) // - (3*x-7)/(x-2)

5/(x^2-x+6)-((3*x-7)/(x-2)) = 0

5/(x^2-x+6)+(-1*(3*x-7))/(x-2) = 0

x^2-x+6 = 0

x^2-x+6 = 0

x^2-x+6 = 0

DELTA = (-1)^2-(1*4*6)

DELTA = -23

DELTA < 0

1 = 0

(-1*(3*x-7))/(x-2)+5 = 0

(5*(x-2))/(x-2)+(-1*(3*x-7))/(x-2) = 0

5*(x-2)-1*(3*x-7) = 0

2*x-3 = 0

(2*x-3)/(x-2) = 0

(2*x-3)/(x-2) = 0 // * x-2

2*x-3 = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x = 3/2

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